CS606 Assignment 1 Solution Spring 2021. Complete guideline with video demonstration and code running example for compiler construction.
Compiler Construction (CS606) Assignment # 01 Spring 2021 | Total marks = 20 Due Date: 21st May, 2021 |
Consider the following stream of characters given as input to the lexical analyzer.
void main ( )
{
int xy = 57, num = 10;
/* variable declaration */
if (xy > num) /* variable declaration */
return ( xy );
else
retrun ( num );
}
After lexical analysis, find the tokens produced with their types as per the following table format.
CS606 Assignment 1 Solution Guideline Spring 2021
#include<iostream>
#include<fstream>
#include<stdlib.h>
#include<string.h>
#include<ctype.h>
using namespace std;
int isKeyword(char buffer[]){
char keywords[32][10] = {"auto","break","case","char","const","continue","default",
"do","double","else","enum","extern","float","for","goto",
"if","int","long","register","return","short","signed",
"sizeof","static","struct","switch","typedef","union",
"unsigned","void","volatile","while"};
int i, flag = 0;
for(i = 0; i < 32; ++i){
if(strcmp(keywords[i], buffer) == 0){
flag = 1;
break;
}
}
return flag;
}
int main(){
char ch, buffer[15], operators[] = "+-*/%=";
ifstream fin("program.txt");
int i,j=0;
if(!fin.is_open()){
cout<<"error while opening the file\n";
exit(0);
}
while(!fin.eof()){
ch = fin.get();
for(i = 0; i < 6; ++i){
if(ch == operators[i])
cout<<ch<<" is operator\n";
}
if(isalnum(ch)){
buffer[j++] = ch;
}
else if((ch == ' ' || ch == '\n') && (j != 0)){
buffer[j] = '\0';
j = 0;
if(isKeyword(buffer) == 1)
cout<<buffer<<" is keyword\n";
else
cout<<buffer<<" is indentifier\n";
}
}
fin.close();
return 0;
}
Output of Program